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A reaction produces 10.5 L if oxygen, but was supposed to produce 1 mol of oxygen. What is the percent yield ? (One mole of any gas occupies 22.4 L under certain conditions of temperature and pressure. Assume those conditions for this question)

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Yna9141
To answer this item, we assume that oxygen behaves ideally such that it is able to fulfill the following equation,

 PV = nRT

If we are to retain constant the variable n and V. 

The percent yield can therefore be solved through the following calculation,

   n = (10.5 L)/(22.4 L)   x 100%

Simplifying,
    n = 46.875%

Answer: 48.87%

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