The perimeter of figure 1 is 18π
The perimeter of figure 2 is 8+18π
The perimeter of figure 3 is 12π+12
The area of figure 1 is 54π
The area of figure 2 is 96
The area of figure 3 is 18π+72
what is the area and perimeter of a semi-circle?
area of semi-circle = 0.5*π*r²
the perimeter of a semi-circle= π*r
the perimeter of figure 1
semi-perimeter of a semicircle with radius 9 and semi-perimeter of three semicircles with radius 3
[tex]\pi*9+3(\pi *3)=18\pi cm[/tex]
area of figure 1= area of a semi-circle with radius 9 and area of 3 semi-circles with radius 3.
[tex]=0.5*\pi *9^2 + 3(0.5*\pi *3^2) = 54\pi[/tex] square cm.
the perimeter of figure 2
AB+FE+ 6* Perimeter of a single semi-circle, since all are having an equal radius
[tex]= 4*2+6*\pi *3 = (8+18\pi) cm[/tex]
Area of figure 2 = area of rectangle AFEB = 8*12 = 96 square cm
the perimeter of figure 3
the perimeter of Semicircles( AE+DC+BC)+ AB+ED
[tex]=6*\pi +3*\pi +3*\pi +6+6=12\pi +12 cm[/tex]
area of figure 3 = area of semi-circle with radius 6 + area of rectangle AEDB = [tex]0.5*\pi *6^2+ 12*6 = 18\pi +72[/tex]
hence,
perimeter & area of all three figures were calculated using the formula of a semi-circle area and the formula of area of a rectangle.
to get more about circles, refer:
https://brainly.com/question/25938845
