Answer:
[tex]\texttt{Material left = }=4\frac{3}{5}yd[/tex]
Step-by-step explanation:
Mai-li has 7 1/5 yd. of material.
[tex]\texttt{Material Mai-li having = }7\frac{1}{5}=\frac{7\times 5+1}{5}=\frac{36}{5}yd[/tex]
Her new skirt will take 2 3/5 yd.
[tex]\texttt{Material needed for skirt = }2\frac{3}{5}=\frac{2\times 5+3}{5}=\frac{13}{5}yd[/tex]
Material left = Material Mai-li having - Material needed for skirt
[tex]\texttt{Material left = }\frac{36}{5}-\frac{13}{5}=\frac{36-13}{5}=\frac{23}{5}\\\\\texttt{Material left = }\frac{20+3}{5}=4\frac{3}{5}yd[/tex]
