Given that hypothesis test with
[tex]H_0:p=0.1 \\ H_a:p\neq0.1[/tex]
where n = 480 and [tex]\hat{p}=0.12[/tex].
The test statistics is given by
[tex]z= \frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}} \\ \\ =\frac{0.12-0.1}{\sqrt{\frac{0.1(1-0.1)}{480}}} \\ \\ = \frac{0.02}{\sqrt{\frac{0.1(0.9)}{480}}} = \frac{0.02}{\sqrt{\frac{0.09}{480}}} \\ \\ = \frac{0.02}{\sqrt{0.0001875}} = \frac{0.02}{0.0137} \\ \\ =1.46[/tex]
