Explain how you would graph the line containing a slope of –1/5 that goes through the point (1,–4).

you would take your point, then graph the point. For slope, remember that it is always rise over run. So you would go down 1 from your origional point, then go to the right 5 times.

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shubhamchouhanvrVT shubhamchouhanvrVT · Answer 2 · 2022-08-02T12:51:33+02:00

The graph of the equation y = (-1/5)(x+19) is explained in the answer.

What is an equation?

An equation is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

It is given that the line containing a slope of –1/5 goes through the point (1,–4). The graph of the equation will be plotted by first finding the equation.

To calculate the equation of the line put the point (1,-4) into the standard equation of the line.

The standard form of the equation of the line is calculated as:-

y = mx + c

y = ( -1 / 5 ) x + c

Put x = 1 and y = -4.

-4 = ( -1 / 5 )(1) + c

c = ( -20 + 1 ) / 5

c = -19 / 5

The equation formed is,

y = ( -1 / 5 ) x + c

y = ( -1 / 5 )x - ( 19 / 5 )

y = ( -1 / 5 )(x + 19 )

The graph of the equation is attached with the answer below.

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