Given two points (x₁,y₁) and (x₂,y₂) the slope of the line that passes through theses points will be:m=(y₂-y₁)/(x₂-x₁) We have two points A(-2,-2) and B(2,-2); therefore the slope will be:m=(-2+2)/(2+2)=0/4=0 slope-intercept form:y=mx +bm=slopeb=y-intercept =-2 y=0x-2y=-2 Answer: The slope of diagonal AB is 0 and its equation is y=-2
