Fido weighs 26 pounds more than fifi. fifi weighs 12 pounds less than rover. if the sum of their weights is 71, how much does fifi weigh?

Hey there,
Let's say Rover's weight is x,
Rover = x
Fifi = x - 12
Fido = x - 12 + 26
x + x - 12 + x - 12 + 26 = 71
3x - 12 - 12 + 26 = 71
3x + 2 = 71
3x = 71 - 2
3x = 69
x = 69 / 3
= 23
Fifi = 23 - 12
= 11 pounds

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Lanuel Lanuel · Answer 2 · 2021-10-19T11:18:34+02:00

After solving the word problem by using the elimination method, Fifi weighs 11 pounds.

Let Fido's weight be F.

Let Fifi's weight be I.

Let Rover's weight be R.

To find how much Fifi weighs:

Translating the word sentence into an algebraic expression, we have:

Fido weighs 26 pounds more than Fifi:

[tex]F = I + 26[/tex] ....equation 1

Fifi weighs 12 pounds less than Rover:

[tex]I = R - 12[/tex] ....equation 2

The sum of their weights is 71:

[tex]F+I+R = 71[/tex] .....equation 3

Substituting eqn 1 and 2 into eqn 3, we have:

[tex]I + 26 + R - 12 + R = 71\\\\I + 2R +14 = 71 \\\\I + 2R = 71 - 14\\\\I + 2R = 57[/tex]....equation 4.

Solving eqn 2 and 4 by elimination method:

[tex]I - R = -12[/tex] (×[tex]2[/tex])

[tex]I + 2R = 57[/tex]

[tex]2I - 2R = -24[/tex]

Adding the two equations together, we have:

[tex]3I = 33\\\\I = \frac{33}{3}[/tex]

I = 11 pounds

Therefore, Fifi weighs 11 pounds.

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