What is the equation of the line shown in the graph? A function graph of a line with two points (-3,-2) and (-1,2) with an x axis of negative five to five and a y axis of negative five to five Drag and drop the expressions to write the equation of the line in slope-intercept form.

What is the equation of the line shown in the graph A function graph of a line with two points 32 and 12 with an x axis of negative five to five and a y axis of class=

Respuesta :

y = mx + b

To find m, the slope:
The rise is +4, the run is +2
4 / 2 is 2.

To find b, the y-intercept:
When x is 0, y is 4.
Therefore the y-intercept is 4.

Plugging it in,
y = 2x + 4
For the first part of the question

y+2/x+3 = 2+2/-3+1
y+2/x+3 = 4/-2
-2(y+2)=4(x+3)
-2y-4=4x+12
in general form: 4x+2y+16=0
in y=mx+b form
-2y=4x+16
y= -2x-8
Q&A Education