A certain gas is present in a 11.0 l cylinder at 3.0 atm pressure. if the pressure is increased to 6.0 atm , the volume of the gas decreases to 5.5 l . find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys boyle's law.

Boyle's law is a special kind of ideal gas equation that can only be applied if the temperature is constant. The derived formula is:

PV= k
which means that there is a constant value for each product of any pressure and volume.

For Ki,
Ki = Pi*Vi = (3 atm)(11 L) = 33 L·atm
For Kf,
Kf = Pf*Vf = (6 atm)(5.5 L) = 33 L·atm

Since Ki = Kf, then the gas obeys Boyle's Law.

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