A water pipe tapers down from an initial radius of r1 = 0.23 m to a final radius of r2 = 0.08 m. the water flows at a velocity v1 = 0.84 m/s in the larger section of pipe. 1) what is the volume flow rate of the water?

The volumetric flow rate is merely the product of the area of the pipe and the velocity. Through continuity equation, we can say that the volumetric flow rate is the same at point 1 and point 2.

V = A₁v₁ = A₂v₂
V = π(0.23m)²(0.84 m/s)
V = 0.14 m³/s

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lhmarianateixeira lhmarianateixeira · Answer 2 · 2022-05-11T10:43:30+02:00

The volume flow rate of the water will be equal to 0.61 m^2/s

What is the flow formula?

We then have a new formula for volumetric flow rate Q = A v Q=Av Q=AvQ, equals, A, v that is often more useful than the original definition, because the area A is easy to determine.

Knowing that:

an initial radius of r1 = 0.23 m
a final radius of r2 = 0.08 m
the water flows at a velocity v1 = 0.84 m/s

So the calculus will be:

[tex]V = A_1v_1 = A_2v_2\\V = \pi(0.23m)(0.84 m/s) \\V = 0.61 m^2/s[/tex]

See more about flow at brainly.com/question/13562310

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