Respuesta :
Hey there! Hope I can be of assistance!
[tex]\frac{mn^2}{mn+m^2n^2} \ \textgreater \ Factor\;mn+m^2n^2 \ \textgreater \ \mathrm{Apply\:exponent\:rule}:\ \:a^{b+c}=a^ba^c[/tex]
[tex]m^2=mm,\:n^2=nn \ \textgreater \ mn+mmnn[/tex]
[tex]\mathrm{Factor\:out\:common\:term\:}mn \ \textgreater \ mn\left(mn+1\right) \ \textgreater \ \frac{mn^2}{mn\left(mn+1\right)}[/tex]
[tex]Cancel\;\frac{mn^2}{mn\left(mn+1\right)} \ \textgreater \ \mathrm{Cancel\:the\:common\:factor:}\:m \ \textgreater \ \frac{n^2}{n\left(mn+1\right)}[/tex]
[tex]\mathrm{Cancel\:the\:common\:factor:}\:n \ \textgreater \ \frac{n}{mn+1}[/tex]
In your case, the answer should be C!
Hope this helps!
[tex]\frac{mn^2}{mn+m^2n^2} \ \textgreater \ Factor\;mn+m^2n^2 \ \textgreater \ \mathrm{Apply\:exponent\:rule}:\ \:a^{b+c}=a^ba^c[/tex]
[tex]m^2=mm,\:n^2=nn \ \textgreater \ mn+mmnn[/tex]
[tex]\mathrm{Factor\:out\:common\:term\:}mn \ \textgreater \ mn\left(mn+1\right) \ \textgreater \ \frac{mn^2}{mn\left(mn+1\right)}[/tex]
[tex]Cancel\;\frac{mn^2}{mn\left(mn+1\right)} \ \textgreater \ \mathrm{Cancel\:the\:common\:factor:}\:m \ \textgreater \ \frac{n^2}{n\left(mn+1\right)}[/tex]
[tex]\mathrm{Cancel\:the\:common\:factor:}\:n \ \textgreater \ \frac{n}{mn+1}[/tex]
In your case, the answer should be C!
Hope this helps!