Answer:
Option B [tex]174.82\ ft[/tex]
Step-by-step explanation:
we know that
In the right triangle ABC
[tex]tan(A)=\frac{BC}{AC}[/tex]
see the attached figure to better understand the problem
we have that
[tex]A=4\°[/tex]
[tex]AC=2,500\ ft[/tex]
[tex]BC=h\ ft[/tex] ----> is the height of the skyscraper
substitute and solve for h
[tex]tan(4\°)=\frac{h}{2,500}[/tex]
[tex]h=2,500*tan(4\°)=174.82\ ft[/tex]
