Answer:
option d
Step-by-step explanation:
We are given with three function
Plug in x=-2 in first function
f(x)= 3 so f(-2) = 3
Plug in x=-2 in second function
[tex]f(x) = -\frac{x}{2} +2[/tex]
[tex]f(-2) = -\frac{-2}{2} +2=3[/tex]
Plug in x=2 in second function
[tex]f(x) = -\frac{x}{2} +2[/tex]
[tex]f(-2) = -\frac{2}{2} +2=1[/tex]
Plug in x=2 in third function
f(x)= 2x-3
f(2)= 2(2) -3 = 1
We can see that f(-2)=3 is same for first and second function
also f(2) = 1 is same for second and third functions
So the graph is continuous
option D satisfies the points
Answer:
it is the 4th graph
Step-by-step explanation:
i know because i just took the test
