Respuesta :

kenmyna
option  B  is  the  answer
 That  is CU2+  oxidized  to  cu, and  Al  reduced   to    Al3+
At  the  the  anode  oxidation  take  place  while at the  cathode  reduction  reaction  take  place.
  copper  metal  is  placed  in  right  hand  side where oxidation  take  place.
  half  reaction  for  oxidation  of  copper  is  as   follows
       cu (s)+3CU^2+  2e-   
Uraniumdavid

Answer: Cu2+ oxidizes to Cu will occur at the anode

Explanation:

Reduction occurs at the cathode and oxidation occurs at the anode

Al2+ reduces to Al3+ so this will occur at the cathode which will be on the left hand

Cu2+ oxidizes to Cu which oxidizes will occurs at the anode which is placed on the right hand

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