Respuesta :

kenmyna
Answer A
That  is cu^2+ reduces  to  CU, and Al  oxidizes  to  Al^3+
  At  the  cathode  reduction  take   place  while  at  the  anode oxidation  take  place.  copper  ions  are  reduce to  copper  metal when  two   electrons  are  added,
 the  half cell  reaction  is  as follows
 3Cu^2+    +   2e-  --> 3CU(s)
lucainkviedma

Answer:

The correct answer is the second.

Explanation:

Oxidation occurs when an element loses electrons, acquiring a positive charge. Reduction occurs when an element gains electrons and goes from a positively charged state to a neutral one.

Aluminum metal (Al) oxidizes, so we say that Al is the reducing species, which acts by reducing [tex]Al^{3+}[/tex]. Copper ([tex]Cu^{2+}[/tex]) is reduced, so it is the oxidizing agent, it acts oxidizing to Cu.

[tex]Cu^{2+}[/tex] oxidizes to Cu, and Al reduces to [tex]Al^{3+}[/tex].

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