[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3500\\
r=rate\to 5.6\%\to \frac{5.6}{100}\to &0.056\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{weekly, thus fifty two}
\end{array}\to &52\\
t=years\to &3
\end{cases}[/tex]
[tex]\bf A=3500\left(1+\frac{0.056}{52}\right)^{52\cdot 3}\implies A=3500\left( \frac{6507}{6500} \right)^{156}
\\\\\\
A\approx 4139.9038869337[/tex]
