Answer:
D) x = +-√7 and x = +-i√2
Step-by-step explanation:
Given:
x^4 -5x^2 -14 = 0
This can be written as
x^4 + 2x^2 - 7x^2 -14 = 0
x^2(x^2 + 2) -7(x^2 + 2) = 0
(x^2 +2)(x^2 - 7) = 0
x^2 + 2 = 0 and x^2 - 7 = 0
x^2 = -2
x = [tex]\sqrt{-2}[/tex]
x = ±i√2
x^2 - 7 = 0
x^2 = 7
x = ±√7
Therefore, solutions are D) x = +-√7 and x = +-i√2
Hope this will helpful.
Thank you.
