Respuesta :
Answer:
2.7%
Step-by-step explanation:
Actual width = 45.5 meters.
Incorrect width = 44.25 meters.
Error = 45.5 - 44.25 = 1.25
Percentage error = [tex]\frac{Error}{Actual width} (100)[/tex]
[tex]=\frac{1.25}{45.5} (100)[/tex]
= 2.74
≈ 2.7%
Hence, the percentage error = 2.7% which is given in the third option.
The percent error in the measurement, to the nearest tenth of a percent, is 2.7%.
Percentages
Given that Karen measures the width of a garden plot and records that it is 44.25 meters, but its actual width is 45.5 meters, to determine what is the percent error in the measurement, to the nearest tenth of a percent, the following must be performed calculation:
- 45.5 = 100
- 44.25 = X
- 44.25 x 100 / 45.5 = X
- 97.25 = X
- 100 - 97.25 = 2.75
Therefore, the percent error in the measurement, to the nearest tenth of a percent, is 2.7%.
Learn more abou percentages in https://brainly.com/question/1691136