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04-12-2017
Chemistry

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How many liters of gas would be formed at 460 ∘c and 1.00 atm pressure by explosion of 560 g of nh4no3?

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luunhatminh199p0focb luunhatminh199p0focb

04-12-2017

NH4NO3 -> NH3 + H2O
n = 560/80 = 7 (mol)
=> n(NH3 + H20) = 7+7 = 14 (mol)
P.V = nRT (R = 22.4/273 = 0.082)
(T = 460 + 273 = 773K)
=> V = (nRT)/P = (14 x 0.082 x 773)/1 = 887.404 (L)

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