Respuesta :
Answer:
406.9 kJ = 407 kJ
Explanation:
**Since there is not much information to go off of, I am going to use values that populated in my assignment but use the moles given in yours to solve so that you can have idea of solving process**
Assuming your reaction looks like this: 2A + B ⇆ 2C + 2D and assuming your standard enthalpy of formation (delta_H) calculated in Part A was 313 kJ/mol...:
The heat absorbed in each mole of A that reacts is 156.5 kJ, therefore...
[tex]\frac{156.5 kJ}{1 mol A} (2.60 mol)[/tex] = 406.9 kJ = 407 kJ of heat absorbed
