Of the molecules below, the bond in is the most polar. of the molecules below, the bond in is the most polar. hi hbr h2 hf hcl

polarity is classified by the difference in two or more atoms that is the electronegativity value (EN)
En for Fluorine =4.0, Bromine=2.96 Chlorine =3.16 Hydrogen=2.1
for the molecules
HF=4.0-2.I=1.9
HCl=3.16-2.1=1.06
Hbr=2.96-2.1=0.86
Hi=2.66-2.1=0.56
H2=2.1-2.1=0
from the EN value above HF has the mast highest value of EN hence it is the most polar.

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jessicaparrilla2016 jessicaparrilla2016 · Answer 2 · 2019-12-19T00:06:26+01:00

Answer:

The compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.

Explanation:

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To calculate the electronegativity of the compounds, the difference in electronegativity of each of the elements is calculated.

The data we need are:

Fluorine = 4.0

Chlorine = 3.16

Hydrogen = 2.1

Bromine = 2.96

Iodo = 2.66

The electronegativity of the compounds is:

HI: 2.66-2.1 = 0.56

HBr: 2.96-2.1 = 0.86

H2: 2.1-2.1 = 0

HF: 4-2.1 = 1.9

HCl: 3.16-2.1 = 1.06

After the calculations, we can conclude that the compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.

Of the molecules below, the bond in ________ is the most polar. of the molecules below, the bond in ________ is the most polar. hi hbr h2 hf hcl

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Of the molecules below, the bond in is the most polar. of the molecules below, the bond in is the most polar. hi hbr h2 hf hcl