Respuesta :
The problem is incomplete. Check the attached file.
If PGas is equal to 1.36 * 10^4
and PAtmos is equal to 1 atm
Plugging that in our formula given in the file. The answer would be:
1.36 * 10^4 / 1 atm = 0.134221564
If PGas is equal to 1.36 * 10^4
and PAtmos is equal to 1 atm
Plugging that in our formula given in the file. The answer would be:
1.36 * 10^4 / 1 atm = 0.134221564
PA = Pgas
PB = Patmos
Further explanation
The pressure on the gas in a confined space is measured using a manometer. One that is used is an open manometer
The manometer is open in the shape of a U tube and is filled with mercury liquid with both ends open. The other end is related to external pressure while the other end is connected to the room where the pressure will be measured
The height of the mercury will change when the end of the tube is connected to the room
The equation used is
P gas = P bar ± Δh
P bar = atmospheric pressure
Δh = difference in mercury height
The + sign if the mercury surface at the tip is associated with the outside water is higher and vice versa, the sign - if the mercury surface is lower
The attached image states that the surface / mercury level at the end connected to the system / room is higher than the open end, by 11 cm - 5.5 cm = 5.5 cmHg, so the amount of gas pressure:
P bar = P atmos = 1 atm = 76 cmHg
P gas = P bar - h
P gas = 76 cmHg - 5.5 cmHg
P gas = 70.5 cmHg = 93992.26 Pa
or we can use the principle of hydrostatic pressure
PA = P gas, PB = Patmos = 1 atm = 101325 Pa
mercury density = 1.36 × 104 kg / m³
Δ h = 5.5 cm = 0.055 m
PA '= PB
PA + pgh = Patmos
Pgas = Patmos - pgh
PG = 101325 Pa - 1.36x10⁴ x 9.8 x 0.055
Pgas - 101325 Pa - 7330.4 Pa
Pgas = 93994.6 Pa
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