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A 250-gram cart starts from rest and rolls down an inclined plane from a height of 0.541m. Determine its speed at the bottom of the incline.

Respuesta :

W0lf93
Δ PE = m g ( h1 - h2 ) = 0.25 * 9.8 ( 0.541 - 0.127 ) = 2.45 * 0.414 = 1.0143 J Δ PE = KE = 1 / 2 m V^2 1 / 2 m V^2 = 1.0143--- v^2 = 1.0143 * 2 / 0.25 = 8.1144 --- v= 2.8486 m/s

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