Respuesta :
You must find the factors of each number...
9 = 1, 3, 3, 9
6 = 1, 2, 3, 6
Next, determine the common multiple...
9 = 1, 3, 3, 9
6 = 1, 2, 3, 6
Therefore, the most groups Lavinia can make without any glasses or mugs left to spare is 3.
9 = 1, 3, 3, 9
6 = 1, 2, 3, 6
Next, determine the common multiple...
9 = 1, 3, 3, 9
6 = 1, 2, 3, 6
Therefore, the most groups Lavinia can make without any glasses or mugs left to spare is 3.
Answer:
The greatest number of groups Lavinia can set out is:
3
Step-by-step explanation:
Lavinia has 9 glasses and 6 mugs .
We know that:
9=3×3
and 6=3×2
So, maximum 3 groups can be set out which contains 3 glasses and 2 mugs each
Hence, the greatest number of groups Lavinia can set out is:
3