Respuesta :
The probability about the car mileage of between 28.8 and 29.2 will be "0.261".
According to the question,
Average gas mileage,
- 29.0 miles/gallon
Standard deviation,
- 0.6 miles/gallon
The probability will be:
→ [tex]p(28.8< x< 29.2) = p(\frac{28.8-290}{0.6}<z<\frac{29.2-29}{0.6} )[/tex]
[tex]= p(-0.34<z<0.133)[/tex]
[tex]= 0.261[/tex]
Thus the above alternative i.e., "option B" is correct.
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