Respuesta :
Refer to the diagram shown below.
Ignore air resistance.
At maximum height, Vy = 0.
Therefore, if the time to reach maximum height is t seconds, then
0 = ( 7.5 m/s) - (9.8 m/s²)*(t s)
t = 7.5/9.8 = 0.7653 s
Note that the horizontal distance traveled is
Vx*t = (7.5 m/s)*(0.7653 s) = 5.74 m
Answer: 0.765 s
Ignore air resistance.
At maximum height, Vy = 0.
Therefore, if the time to reach maximum height is t seconds, then
0 = ( 7.5 m/s) - (9.8 m/s²)*(t s)
t = 7.5/9.8 = 0.7653 s
Note that the horizontal distance traveled is
Vx*t = (7.5 m/s)*(0.7653 s) = 5.74 m
Answer: 0.765 s
We are only interested in the vertical motion of the ball, in order to solve the problem.
The vertical motion of the ball is an uniformly accelerated motion, with constant acceleration [tex]a=g=-9.81 m/s^2[/tex] (acceleration of gravity). Therefore, the vertical velocity at time t is given by
[tex]v_y (t) = v_{y0} +at[/tex]
where [tex]v_{y0}=7.5 m/s[/tex] is the initial vertical velocity of the ball.
The ball reaches its highest point when [tex]v_y(t)=0[/tex]: therefore, substituting this information into the equation, we can calculate the time t at which this happens:
[tex]0=v_{y0}+at[/tex]
[tex]t=-\frac{v_{0y}}{a}=-\frac{7.5 m/s}{9.81 m/s^2}=0.765 s[/tex]