A snowball is thrown with an initial x velocity of 7.5 m/s and an initial y velocity of 7.5 m/s . How much time is required for the snowball to reach its highest point? (Hint: The highest point of a projectile corresponds to the time when vy,f=0.)

Respuesta :

Refer to the diagram shown below.

Ignore air resistance.
At maximum height, Vy = 0.
Therefore, if the time to reach maximum height is t seconds, then
0 = ( 7.5 m/s) - (9.8 m/s²)*(t s)
t = 7.5/9.8 = 0.7653 s

Note that the horizontal distance traveled is
Vx*t = (7.5 m/s)*(0.7653 s) = 5.74 m

Answer: 0.765 s

Ver imagen Аноним

We are only interested in the vertical motion of the ball, in order to solve the problem.

The vertical motion of the ball is an uniformly accelerated motion, with constant acceleration [tex]a=g=-9.81 m/s^2[/tex] (acceleration of gravity). Therefore, the vertical velocity at time t is given by

[tex]v_y (t) = v_{y0} +at[/tex]

where [tex]v_{y0}=7.5 m/s[/tex] is the initial vertical velocity of the ball.

The ball reaches its highest point when [tex]v_y(t)=0[/tex]: therefore, substituting this information into the equation, we can calculate the time t at which this happens:

[tex]0=v_{y0}+at[/tex]

[tex]t=-\frac{v_{0y}}{a}=-\frac{7.5 m/s}{9.81 m/s^2}=0.765 s[/tex]

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