Respuesta :
Refer to the diagram shown below.
Let
x = m∠J
y = m∠K
z = m∠L
Angle L is thirteen more than angle K, therefore
z = y + 13 (1)
Angle J is seven times more than six times angle K, therefore
x = 7(6y) = 42y (2)
The sum of the angles in the triangle is 180°, therefore
x + y + z = 180 (3)
Substitute (1) and (2) into (3).
42y + y + (y + 13) = 180
44y + 13 = 180
44y = 167
y = 3.8°
x = 42y = 159.4°
z = y + 13 = 16.8°
Answer:
m∠J = 159.4°
m∠K = 3.8°
m∠L = 16.8°
Let
x = m∠J
y = m∠K
z = m∠L
Angle L is thirteen more than angle K, therefore
z = y + 13 (1)
Angle J is seven times more than six times angle K, therefore
x = 7(6y) = 42y (2)
The sum of the angles in the triangle is 180°, therefore
x + y + z = 180 (3)
Substitute (1) and (2) into (3).
42y + y + (y + 13) = 180
44y + 13 = 180
44y = 167
y = 3.8°
x = 42y = 159.4°
z = y + 13 = 16.8°
Answer:
m∠J = 159.4°
m∠K = 3.8°
m∠L = 16.8°
Answer:
m∠J = 159.4°
m∠K = 3.8°
m∠L = 16.8°
Step-by-step explanation:
Refer to the diagram shown below.
Let
x = m∠J
y = m∠K
z = m∠L
Angle L is thirteen more than angle K, therefore
z = y + 13 (1)
Angle J is seven times more than six times angle K, therefore
x = 7(6y) = 42y (2)
The sum of the angles in the triangle is 180°, therefore
x + y + z = 180 (3)
Substitute (1) and (2) into (3).
42y + y + (y + 13) = 180
44y + 13 = 180
44y = 167
y = 3.8°
x = 42y = 159.4°
z = y + 13 = 16.8°