ekids22
contestada

HELP!!!

Sarah wants to hang a mirror in her room. The mirror and frame must have an area of 15 square feet. The mirror is 3 feet wide and 4 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?

3x2 + 14x − 2 = 0
4x2 + 14x − 3 = 0
x2 + 12x − 14 = 0
2x2 + 7x − 14 = 0

HELP Sarah wants to hang a mirror in her room The mirror and frame must have an area of 15 square feet The mirror is 3 feet wide and 4 feet long Which quadratic class=

Respuesta :

length of the outer frame: 4+2x
width of the outer frame: 3+2x
area of the outframe: (4+2x)(3+2x)=15
expand the equation: 12+8x+6x+12x^2=15
combine like terms: 4x^2+14x-3=0

The quadratic equation which is used to determine the thickness of the frame is [tex]4x^{2} +14x-3=0[/tex]

What is quadratic equation?

"Quadratic equation is an algebraic equation of the second degree in x. The standard form of an quadratic equation is [tex]ax^{2} +bx+c[/tex]"

Let the width of the outer frame be 3+x

Let the length of the outer frame be 4+x

Area of the outer frame = 15 square feet

Therefore,

(3+2x)(4+2x) = 15

[tex]12+6x+8x+4x^{2} =15\\4x^{2} +14x+12-15=0\\4x^{2} +14x-3=0[/tex]

Hence, the quadratic equation that determines the thickness of the outer frame is [tex]4x^{2}+14x-3=0[/tex]

To learn more about quadratic equation here

https://brainly.com/question/16315200

#SPJ2

Otras preguntas

Q&A Education