Respuesta :
calculate the mass of the empirical formula
C=12
H=1
O=16
C3H3O = 12*3+1*3+16= 55
divide the molar mass by the empirical mass
110.0/55 = 2
the molecular formula will be
(C3H3O)2 or C6H6O2
C=12
H=1
O=16
C3H3O = 12*3+1*3+16= 55
divide the molar mass by the empirical mass
110.0/55 = 2
the molecular formula will be
(C3H3O)2 or C6H6O2
[tex](C_3H_3O)_2[/tex] or [tex]C_6H_6O_2[/tex] is the molecular formula of the compound.
What is an empirical formula?
A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule [tex]CH_2O[/tex]is the empirical formula for glucose.
Calculate the mass of the empirical formula:
C=12
H=1
O=16
[tex]C_3H_3O[/tex] = 12*3+1*3+16= 55
Divide the molar mass by the empirical mass:
110.0÷55
= 2
The molecular formula will be:
[tex](C_3H_3O)_2[/tex] or [tex]C_6H_6O_2[/tex]
Learn more about empirical formula here:
https://brainly.com/question/14044066
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