Respuesta :
Originally, there are 10 white golf balls and 6 striped golf balls.
The ratio of white to striped balls is
10/6 = 5/3
Let 112 more balls be added, so that
w = white balls are added
s = striped balls are added.
Then w + s = 112 (1)
To preserve the ratio of white to striped balls,
(10 + w)/(6 +s) = 5/3.
That is (by cross multiplying),
3(10 + w) = 5(6 + s) (2)
30 + 3w = 30 + 5s
3w = 5s
w = (5/3)s (3)
Substitute (3) into (1).
(5/3)s + s = 112
(8/3)s = 112
s = (3/8)*112 = 42
w = (5/3)*42 = 70
Answer
70 white balls added
42 striped balls added
The ratio of white to striped balls is
10/6 = 5/3
Let 112 more balls be added, so that
w = white balls are added
s = striped balls are added.
Then w + s = 112 (1)
To preserve the ratio of white to striped balls,
(10 + w)/(6 +s) = 5/3.
That is (by cross multiplying),
3(10 + w) = 5(6 + s) (2)
30 + 3w = 30 + 5s
3w = 5s
w = (5/3)s (3)
Substitute (3) into (1).
(5/3)s + s = 112
(8/3)s = 112
s = (3/8)*112 = 42
w = (5/3)*42 = 70
Answer
70 white balls added
42 striped balls added
Answer:
Step-by-step explanation:
Originally, there are 10 white golf balls and 6 striped golf balls.
The ratio of white to striped balls is
10/6 = 5/3
Let 112 more balls be added, so that
w = white balls are added
s = striped balls are added.
Then w + s = 112 (1)
To preserve the ratio of white to striped balls,
(10 + w)/(6 +s) = 5/3.
That is (by cross multiplying),
3(10 + w) = 5(6 + s) (2)
30 + 3w = 30 + 5s
3w = 5s
w = (5/3)s (3)
Substitute (3) into (1).
(5/3)s + s = 112
(8/3)s = 112
s = (3/8)*112 = 42
w = (5/3)*42 = 70
Answer
70 white balls added
42 striped balls added
