The equation shows the reaction between zinc metal and hydrochloric acid.


Zn(s) + 2HCl(aq) mc014-1.jpg ZnCl2(aq) + H2(g)


What is the theoretical yield of hydrogen gas if 5.00 mol of zinc are added to an excess of hydrochloric acid?
a.5.05 g
b.10.1 g
c.182 g
d.682 g

Respuesta :

Answer: 10 grams of Hydrogen gas will be produced theoretically.

Explanation: The equation for the reaction between zinc metal and hydrochloric acid is:

[tex]Zn(s)+2HCl(aq.)\rightarrow ZnCl_2(aq.)+H_2(g)[/tex]

As HCl is present in excess, therefore limiting reagent is Zinc metal as it limits the formation of product.

By stoichiometry,

1 mole of Zinc metal produces 1 mole of Hydrogen gas, therefore

[tex]\text{5 moles of Zinc metal will produce}=\frac{1}{1}\times 5=5\text{ moles of Hydrogen gas}[/tex]

Amount of Hydrogen gas produced can be calculated by:

[tex]\text{Mass of gas produced}=\text{Moles}\times \text{Molar mass}[/tex]

Molar mass of Hydrogen = 2 g/mol

Mass of hydrogen gas produced = (5 moles )× (2 g/mol)

Mass of hydrogen gas produced = 10 grams

Answer:

10.1g

Explanation:

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