Respuesta :
well, the cheap answer is
f(x) = -3| x - 1 | is really just f(x) = -3| x - 1 | + 0.
now, what value of "x" makes the absolute value expression to 0?
well, let's just set it to 0 and check,
x - 1 = 0
x = 1
so if "x" ever becomes 1, the | x - 1| will turn to 0, therefore, the vertex is at
f(x) = -3| (1) - 1 | + 0 --------------> ( 1, 0 )
f(x) = -3| x - 1 | is really just f(x) = -3| x - 1 | + 0.
now, what value of "x" makes the absolute value expression to 0?
well, let's just set it to 0 and check,
x - 1 = 0
x = 1
so if "x" ever becomes 1, the | x - 1| will turn to 0, therefore, the vertex is at
f(x) = -3| (1) - 1 | + 0 --------------> ( 1, 0 )
Using concepts of the absolute value function, it is found that the vertex is at (1,0).
The general absolute value function can be modeled as:
[tex]f(x) = a|x - b| + c[/tex]
The vertex is at (b,c).
In this problem, the function is:
[tex]f(x) = -3|x - 1|[/tex]
Thus, [tex]a = -3, b = 1, c = 0[/tex], which means that the vertex is at (1,0), which is confirmed by the sketch of the graph at the end of this answer.
A similar problem is given at https://brainly.com/question/24559165