D)The hiker had an easy, level trail from 11:00-12:00 and was able to travel the fastest during that time period.
Explanation:
In the table, we see that the duration of the 4 time intervals is always the same (1 h). The velocity of the hiker during each part of the trail is given by
[tex]v=\frac{d}{t}[/tex]
where d is the displacement and t is the time taken.
By applying this formula, we can see that the hiker had the fastest velocity during 11.00 and 12.00, so statement D is correct. In fact, the velocity of the hiker in the 4 parts is:
-10.00-11.00 : [tex]v=\frac{2 m}{1 h}=2 mph[/tex]
-11.00-12.00 : [tex]v=\frac{4 m}{1 h}=4 mph[/tex]
-12.00-1.00 : [tex]v=\frac{1 m}{1 h}=1 mph[/tex]
-1.00-2.00 : [tex]v=\frac{3 m}{1 h}=3 mph[/tex]
So, we see that the hiker walked fastest between 11.00 and 12.00.
