megan1205
megan1205
01-11-2017
Mathematics
contestada
Can someone help me solve these?
Respuesta :
choixongdong
choixongdong
01-11-2017
12anb^0/ 4an^5
= 3 / n^4
answer
3 / n^4
-----------
20a^-3bn^0 / 15a^-2b^4
= 4a^-1 / 3b^3
= 4 / (3ab^3)
or
4
---------
3ab^3
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