You and your friend are rolling number cubes. Each cube has 6 sides with the numbers 1 to 6. If a sum of 7 is rolled, your friend gets 1 point. If a 2, 3, or 4 is rolled, you get 1 point. After 108 rolls each, what scores should you expect?

Friend: 54; You: 54

Friend: 18; You: 18

Friend: 54; You: 18

Friend: 18; You: 54

Respuesta :

Friend: 18; you: 54
Because you have much bigger chance

Answer:

Friend: 18; You: 54

Step-by-step explanation:

You and your friend are rolling number cubes.

Each cube has 6 sides with the numbers 1 to 6.

Total Outcomes=36

{1,1};{1,2};{1,3}{1,4};{1,5};{1,6}

{2,1};{2,2};{2,3}{2,4};{2,5};{2,6}

{3,1};{3,2};{3,3}{3,4};{3,5};{3,6}

{4,1};{4,2};{4,3}{4,4};{4,5};{4,6}

{5,1};{5,2};{5,3}{5,4};{5,5};{5,6}

{6,1};{6,2};{6,3}{6,4};{6,5};{6,6}

If a sum of 7 is rolled, your friend gets 1 point.

Favorable outcomes for friend = {1,6};{2,5};{3,4};{4,3};{5,2};{6,1}=6

Total outcomes = 36

So, probability of getting a sum of 7 =[tex]\frac{6}{36}=\frac{1}{6}[/tex]

Since there are 108 rolls

So, expected score of friend = [tex]108 \times \frac{1}{6}=18[/tex]

If a 2, 3, or 4 is rolled, you get 1 point.

So, probability of getting 2 = [tex]\frac{1}{6}[/tex]

So, probability of getting 3 = [tex]\frac{1}{6}[/tex]

So, probability of getting 4 = [tex]\frac{1}{6}[/tex]

So, So, probability of getting 2,3 or 4 = [tex]\frac{1}{6}+\frac{1}{6}+\frac{1}{6} =\frac{3}{6} =\frac{1}{2}[/tex]

So, your expected score = [tex]108 \times \frac{1}{2}=54[/tex]

So, option D is correct.

Hence expected score of friend is 18 and yours expected score is 54

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