[tex] \frac{-1}{8c} =2[/tex]
This requires that c ≠ 0 , meaning c≠0
[tex] \frac{-1}{8c} =2[/tex]
Multiply by x to eliminate var in denominator
[tex] \frac{ \not c*(-1)}{ 8 \not c} =c*2[/tex]
[tex] \frac{-1}{8} =c*2[/tex]
Common denominator is 8
[tex] \frac{\not 8(-1)}{\not 8} =8c*2[/tex]
[tex]-1=8c*2[/tex]
[tex]-1=16c[/tex]
[tex]x=-16[/tex]
The answer is: b. -16
