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05-10-2017
Mathematics

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find cubic function given the zeroes 3, -4, and 6

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05-10-2017

[tex]\mathsf{(x-3)\cdot(x+4)\cdot(x-6)=0}\\ \\ \mathsf{(x^2+4x-3x-12)\cdot(x-6)=0}\\ \\ \mathsf{(x^2+x-12)\cdot(x-6)=0}\\ \\ \mathsf{x^3-6x^2+x^2-6x-12x+72=0}\\ \\ \boxed{\mathsf{x^3-5x^2-18x+72=0}}[/tex]

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