Respuesta :
try plugging them in, might seem tedious, but it's the best way to practice. if you plug in a pair and the left side of the equation is less than or equal to 6, it's the right answer.
we have
[tex]2y-x\leq -6[/tex]
we know that
if a ordered pair is a solution of the inequality
then
the ordered pair must satisfy the inequality
we will proceed to verify each case to determine the solution of the problem
case A) [tex](0,-3)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-3)-0\leq -6[/tex]
[tex]-6\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](0,-3)[/tex] is a solution of the inequality
case B) [tex](2,-2)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-2)-2\leq -6[/tex]
[tex]-6\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](2,-2)[/tex] is a solution of the inequality
case C) [tex](1,-4)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-4)-1\leq -6[/tex]
[tex]-9\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](1,-4)[/tex] is a solution of the inequality
case D) [tex](6,1)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(1)-6\leq -6[/tex]
[tex]-4\leq -6[/tex] -------> Is False
therefore
the ordered pair [tex](6,1)[/tex] is not a solution of the inequality
case E) [tex](-3,0)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(0)-(-3)\leq -6[/tex]
[tex]3\leq -6[/tex] -------> Is False
therefore
the ordered pair [tex](-3,0)[/tex] is not a solution of the inequality
therefore
the answer is
[tex](0,-3)[/tex]
[tex](2,-2)[/tex]
[tex](1,-4)[/tex]