How many grams of Hydrogen (H) would need to react with 190 grams of Fluorine (F) to make 200 grams of HF (Hydrofluoric Acid)? Question 6 options: 200 20 10 5

mol weight of HF = 1 + 19 = 20 g/mol HF

200 g HF * ( 1 mol / 20 g HF) = 10 mol HF

The stoichiometry is 1:1 for H:F
So you need; 10 mol H & 10 mol F

mol weight of H = 1 g/mol
10 mol H * (1 g/mol) = 10 g H

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transitionstate transitionstate · Answer 2 · 2018-11-07T04:46:02+01:00

Answer:

10 g of H₂

Solution:

The Balance chemical equation is as follow,

F₂ + H₂ → 2 HF

Step 1: Calculate Amount of F₂ required to form 200 g of HF:

According to balance equation,

40 g (2 mol) HF is formed by = 38 g (1 mol) of F₂

So,

200 g of HF will be formed by = X g of F₂

Solving for X,

X = (200 g × 38 g) ÷ 40 g

X = 190 g of F₂

Step 2: Calculate amount of H₂ to react with 190 g of F₂:

According to equation,

38 g (1 mol) F₂ required = 2 g (1 mol) of H₂

So,

190 g of F₂ will require = X g of H₂

Solving for X,

X = (190 g × 2 g) ÷ 38 g

X = 10 g of H₂