PLS HALP MEH!!!! A soccer ball is kicked from the ground in an arc defined by the function,h(x) = -2x^2 + 8x. What is the height of the ball after 3 seconds?

Respuesta :

CreepN
[tex] h(3) = -2(3)^{2} + 8(3)[/tex]
-2(9) + 24
-18 + 24
h(3) = 6

Answer:

6 feet

Step-by-step explanation:

A soccer ball is kicked from the ground in an arc defined by the function,

[tex]h(x) = -2x^2 + 8x[/tex]

h(x) is the height of the ball and time is t.

we need to find out the height when t= 3 seconds

Plug in 3 for t

[tex]h(x) = -2x^2 + 8x[/tex]

[tex]h(3) = -2(3)^2 + 8(3)[/tex]

[tex]h(3) =-18+24=6[/tex]

The height of the ball after 3 seconds is 6 feet.

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