Answer:
[tex]\rho_{stone} = \frac{56 g}{25 mL} = 2.24 g/mL[/tex]
Explanation:
Mass of the cylinder = 80 g
water added in the cylinder = 20 mL
mass of water + cylinder = 100 g
mass of water added = 100 g - 80 g = 20 g
density of water = [tex]\frac{mass}{volume}[/tex]
[tex]\rho = \frac{20 g}{20 mL} = 1 gm/mL[/tex]
now when stone is put into the cylinder then the volume reached to 45 mL
so volume displaced by the stone = 45 mL - 20 mL
V = 25 mL
mass of stone = 156 g - 100 g = 56 g
now density of stone is
[tex]\rho_{stone} = \frac{mass}{volume}[/tex]
[tex]\rho_{stone} = \frac{56 g}{25 mL} = 2.24 g/mL[/tex]