I can;t answer this question without any context. However, I found a similar problem with a given illustration as shown in the first picture attached. The angle is said to be 17°. The free body diagram is constructed as shown in the second picture attached. The solution is as follows:
∑Fy = 0
Fn = Wy
Fn = Wcos17° = (0.27 kg)(cos 17°) = 0.258 N
∑Fx = 0
Ff - Wx = 0
Ff = Wsin17° = (0.27 kg)(sin 17°) = 0.079 N
Thus, the magnitude of the frictional force is 0.079 N.
