Working formula:
y = v*t + 0.5*a*t^2
where:
y = vertical distance = -1 m
v = initial velocity = 1.25m/s
a = acceleration = 9.81 m/s^2
t = time
Required: t
Solution:
y = v*t + 0.5*a*t^2
1 = (1.25)*t + 0.5*9.81*t^2
0 = -1 + 1.25t + 4.905t^2
Applying completing the square, we get
t = 0.342 s, - 0.597s
Technically, we don't have time with negative value. Thus, the answer is t = 0.342 seconds
