Respuesta :
width=w
length=l
w+2=l
2(w+l)=88
2(w+w+2)=88
2(2w+2)=88
4w+4=88
4w=84
w=21
21+2=23
The length of a rectangle if the perimeter is 88 inches and the length is 2 inches more than the width is 23.
length=l
w+2=l
2(w+l)=88
2(w+w+2)=88
2(2w+2)=88
4w+4=88
4w=84
w=21
21+2=23
The length of a rectangle if the perimeter is 88 inches and the length is 2 inches more than the width is 23.
The length of a rectangle is 33 inches.
What is a rectangle?
The rectangle is a 2D shape having four sides and the opposite sides of the rectangle are equal and parallel. The sum of all angles of the rectangle is 360°.
We have,
The perimeter of the rectangle = 88 inches
And,
The length is 2 inches more than the width.
Now, Let,
Width of the rectangle = a
So,
Length of the rectangle = 3a
Now,
Using the formula of the perimeter of the rectangle,
i.e.
The perimeter of the rectangle = 2(Length + Width)
Now,
According to the question,
i.e.
88 = 2( 3a + a)
i.e.
8a = 88
We get,
a = 11,
i.e.
Width of the rectangle = a = 11 inches
So,
Length of the rectangle = 3a = 3 * 11 = 33 inches
Hence, we can say that the length of a rectangle is 33 inches and the width of the rectangle is 11 inches.
To know more about rectangles click here
https://brainly.com/question/10046743
#SPJ2
