Respuesta :
for this question you need to form two equation and do simultaneous equation.
first you need to let A tickets to be x and B tickets to be y.
the first equation is 10x+60y=6000
the second equation is x+y=500
use one of the equation and make the one expression the subject. so i choose equation two.
x+y=500
x=500-y (equation 3)
sub equation 3 into equation 1,
10x+60y=6000
10(500-y)+60y=6000
5000-10y+60y=6000
50y=1000
y=20 tickets
sub y=20 into equation 3,
x=500-20
x=480 tickets
therefore,
A tickets= 480 tickets
B tickets =20 tickets
therefore the answer is D.
first you need to let A tickets to be x and B tickets to be y.
the first equation is 10x+60y=6000
the second equation is x+y=500
use one of the equation and make the one expression the subject. so i choose equation two.
x+y=500
x=500-y (equation 3)
sub equation 3 into equation 1,
10x+60y=6000
10(500-y)+60y=6000
5000-10y+60y=6000
50y=1000
y=20 tickets
sub y=20 into equation 3,
x=500-20
x=480 tickets
therefore,
A tickets= 480 tickets
B tickets =20 tickets
therefore the answer is D.