Answer:
Time taken, t = 30 seconds
Explanation:
It is given that,
Initial speed of the rocket, u = 0
It is lifted with a constant acceleration of, [tex]a=2\times 10^1\ m/s^2=20\ m/s^2[/tex]
Height to be attained, [tex]d=9\times 10^3\ m[/tex]
Let t is the time taken by the rocket to reach an altitude of [tex]9\times 10^3\ m[/tex]. Using the second equation of kinematics to find it as :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
[tex]d=\dfrac{1}{2}at^2[/tex]
[tex]t=\sqrt{\dfrac{2d}{a}}[/tex]
[tex]t=\sqrt{\dfrac{2\times 9\times 10^3}{20}}[/tex]
t = 30 seconds
So, the time taken by the rocket to reach given height is 30 seconds. Hence, this is the required solution.
