Answer:
[tex]\sin\dfrac{5\pi}{4}=-\dfrac{1}{\sqrt{2}}[/tex]
[tex]\cos\dfrac{5\pi}{4}=-\dfrac{1}{\sqrt{2}}[/tex]
[tex]\tan\dfrac{5\pi}{4}=1[/tex]
Step-by-step explanation:
Given : [tex]\theta =\dfrac{5\pi}{4}[/tex]
The angle is on radian.
We need to find the sine, cosine and tangent.
[tex]\sin\theta =\sin(\frac{5\pi}{4}[/tex]
[tex]\sin\theta =\sin(\pi+\frac{\pi}{4}[/tex]
[tex]\sin\theta =-\sin(\frac{\pi}{4}[/tex] [tex]\because \sin(\pi+\theta)=-\sin\theta[/tex]
[tex]\sin\dfrac{5\pi}{4}=-\dfrac{1}{\sqrt{2}}[/tex]
[tex]\cos\theta =\cos(\frac{5\pi}{4}[/tex]
[tex]\cos\theta =\cos(\pi+\frac{\pi}{4}[/tex]
[tex]\cos\theta =-\cos(\frac{\pi}{4}[/tex] [tex]\because \cos(\pi+\theta)=-\cos\theta[/tex]
[tex]\cos\dfrac{5\pi}{4}=-\dfrac{1}{\sqrt{2}}[/tex]
[tex]\tan\theta =\tan(\frac{5\pi}{4}[/tex]
[tex]\tan\theta =\tan(\pi+\frac{\pi}{4}[/tex]
[tex]\tan\theta =\tan(\frac{\pi}{4}[/tex] [tex]\because \tan(\pi+\theta)=\tan\theta[/tex]
[tex]\tan\dfrac{5\pi}{4}=1[/tex]
