Simultaneous equations can be solved if the number of unknown variables are equal to the number of equations. In the geometry question, the equations are given by the relationship between the lines and angles
Part A
m = 7°, p = 10°, t = 5°, a = 6, and s = 2°
Part B
Arranging the variables from least to greatest gives; stamp
A stamp sits at the corner of an envelope but travels around the world
Part A
From the diagram, we have;
H is a vertical angle to the 90° angle
(7·m + 3)° + 90° + (8·m - 18)° = 180° (linear angles)
∴ (7·m + 3)° + (8·m - 18)° = 180° - 90° = 90°
(15·m - 15)° = 90°
15·m = 90°+ 15° = 105°
m = 105°/15 = 7°
m = 7°
(7·m + 3)° = (5·p + 2)° (vertically opposite angle theorem)
∴ (5·p + 2)° = (7 × 7 + 3)° = 52°
p = (52° - 2°)/5 = 10°
p = 10°
(8·m - 18)° = (11·t - 17)° (vertically opposite angle theorem)
∴ (8 × 7 - 18)° = (11·t - 17)°
38° = (11·t - 17)°
11·t = 38° + 17° = 55°
t = 55°/11 = 5°
t = 5°
CD = 5·a + 12 and DE = 9·a - 12 are congruent segments
5·a + 12 = 9·a - 12 (Definition of congruent segments)
9·a - 5·a = 12 + 12 = 24
4·a = 24
a = 24/4 = 6
a = 6
(21·s + 6° and 48° are congruent congruent angles
21·s + 6° = 48° (Definition of congruent angles)
∴ s = (48° - 6°)/21 = 2°
s = 2°
Part B
Arranging the values of the variables from least to most gives;
s = 2°
t = 5°
a = 6
m = 7°
p = 10°
Which gives;
The answer to the riddle = s, t, a, m, p = Stamp
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