What are the x and y-intercepts of the line described by the equation? 3x−9y=10.8 Enter your answers, in decimal form, in the boxes.

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choixongdong choixongdong · Answer 1 · 2017-10-04T16:25:46+02:00

3x−9y=10.8

x-intercept when y = 0
3x =10.8
x = 3.6

y-intercept when x = 0
−9y=10.8
y = - 1.2

answer

x-intercept (3.6, 0)
y-intercept (0, -1.2)

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ColinJacobus ColinJacobus · Answer 2 · 2019-06-10T17:47:08+02:00

Answer: The x-intercept and y-intercept of the given line are (3.6, 0) and (0, -1.2) respectively.

Step-by-step explanation: We are given to find the x-intercepts and y-intercepts of the line described by the following equation :

[tex]3x-9y=10.8~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

We know that

the x-intercept of a line is the point where the y co-ordinate is 0. Similarly, y-intercept is the point where the x co-ordinate is 0.

Substituting y = 0 in equation (i), we get

[tex]3x-9\times0=10.8\\\\\Rightarrow 3x-0=10.8\\\\\Rightarrow 3x=10.8\\\\\Rightarrow x=\dfrac{10.8}{3}\\\\\Rightarrow x=3.6.[/tex]

So, x-intercept is (3.6, 0).

And substituting x = 0 in equation (i), we get

[tex]3\times 0-9y=10.8\\\\\Rightarrow 0-9y=10.8\\\\\Rightarrow 9y=-10.8\\\\\Rightarrow y=-\dfrac{10.8}{9}\\\\\Rightarrow y=-1.2.[/tex]

So, y-intercept is (0, -1.2).

Thus, the x-intercept and y-intercept of the given line are (3.6, 0) and (0, -1.2) respectively.