veroalvarez4092 veroalvarez4092

04-10-2017
Mathematics

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Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 3t3dxdt+5x−3=03t3dxdt+5x−3=0.

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LammettHash LammettHash

05-10-2017

If [tex]x(t)=k[/tex] is constant, then [tex]\dfrac{\mathrm dx}{\mathrm dt}=0[/tex], so you have

[tex]5k-3=0\implies k=\dfrac35[/tex]

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